2x + 3y = 15 and x - 3y = 3 What's the ordered pair

x = 6

y = 1

Step-by-step explanation:

to solve this system of equation we say let

2x + 3y = 15 equation 1

x - 3y = 3 equation 2

from equation 2

x - 3y = 3 equation 2

x = 3 + 3y equation3

substitute for x in equation 1

2x + 3y = 15 equation 1

2(3+3y) + 3y = 15

6 + 6y + 3y = 15

9y = 15 -6 combining the like terms

9y = 9

divide both sides by the coefficient of y

9y/9 = 9/9

y =1

put y = 1 in equation 3

x = 3 + 3y equation3

x = 3 + 3(1)

x = 3 +3

x = 6

therefore the value of  x is 6 and y is 1 respectively

it should be a and d. lmk if i'm wrong xd

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step-by-step explanation: