A sample of 71 eggs yields a sample mean weight of 2.00 ounces. Assuming that the population standard deviation = 0.590 ounces, find the standard error of the mean in estimating a confidence interval estimate for the true population mean weight at the 95% level of confidence. Round your answer to three decimal places

0.070 is the standard error of the mean weight in estimating a confidence interval estimate        

Step-by-step explanation:

We are given the following in the question:

Sample mean, =  2.00 ounces

Sample size, n = 71

Alpha, α = 0.05

Population standard deviation, σ = 0.590 ounces

Formula for standard error =

Putting values, we get,

Thus, 0.070 is the standard error of the mean weight in estimating a confidence interval estimate

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

idk

step-by-step explanation: