Write a system of equations with a solution (4,–3)

1.       So we have the system of equation. (4, -3)
let’s create another system of equation.
Let a = 4
and Let b = -3
First equation
=> Let’s pick any numbers to be used. Let’s have number 5
=> 5a + 5b
=> 5 (4) + 5 (-3)
=> 20 + (-15)
negative and positive is equals to negative
=> 20 – 15
=> 5 (this the first value of our equation, let this be the value of X)

Second
=> Pick another number, Let’s have 6
=> 6a + 6b
=> 6 (4) + 6 (-3)
=> 24 + (-18)
=> 24 – 18
=> 6 (this is the value of our second equation, let this value be Y)

Now, we have (A, B) = (4, -3) and (X, Y) = (5,6)