The weights of bags of baby carrots are normally distributed, with a mean of 34 ounces and a standard deviation of .35 ounces. bags in the upper 4.5% are too ehavy and must be repackaged. what is the most a bag of baby carrots can weigh and does not need to be repackaged

The carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 34 ounces

Standard Deviation, σ = 0.35 ounces

We are given that the distribution of weights of bags is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.045

Calculation the value from standard normal z table, we have,  

Thus, the carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.