The amount of bacteria in a petri dish increases at a rate proportional to the amount present. At time t=0, the amount of bacteria in the dish is 10 grams. At time t=2, the amount of bacteria in the dish is 30 grams. What is the amount of bacteria in the dish at time t=6 ?

Step-by-step explanation:

Formula to be used is N=N0e^(kt)

N0 - amount of bacteria at time 0, which is 10g

t=2, 30g

30 = 10*e^(k*2)

3 = e^(2k)

2k = ln3

k = 0.5ln3

At t=6:

N = 10*e^(0.5ln3*6)

N = 10e^(3ln3)

N = 10e^ln27

N = 10*27 =270

So the amount of bacteria at t=6 is 270

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

the answer is 1/4

step-by-step explanation: