Mathematics, 30.03.2020 23:16 meganwintergirl

The internet connection speed at any time from your home can depend on the amount of overall internet traffic at that time. Let the random variable X denote the speed of connection in megabits per second (MBPS). Assuming X is uniformly distributed on the interval 0.75 to 1.25 MBPS, answer the following questions

a) Find the mean connection speed and standard deviation.

b) What is the probability that the connection speed will be less than 0.8 MBPS at any given time?

c) What is the probability that the connection speed will be between 0.875 MBPS and 1.125 MBPS at any given time?

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Answer from: andregijoe41

a) The mean connection speed is 1 MBPS and the standard deviation is 0.1443 MBPS.

b) 10% probability that the connection speed will be less than 0.8 MBPS at any given time

c) 50% probability that the connection speed will be between 0.875 MBPS and 1.125 MBPS at any given time

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the distribution is:

$M = \frac{a + b}{2}$

The standard deviation of the distribution is:

$S = \sqrt{\frac{(b-a)^{2}{12}}$

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

The probability that we find a value of x between two values, c and d, d greater than c, is given by

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Assuming X is uniformly distributed on the interval 0.75 to 1.25 MBPS, answer the following questions

This means that a = 0.75, b = 1.25

a) Find the mean connection speed and standard deviation.

$M = \frac{a + b}{2} = \frac{0.75 + 1.25}{2} = 1$

$S = \sqrt{\frac{(b-a)^{2}{12}} = \sqrt{\frac{(1.25 - 0.75)^{2}{12}} = 0.1443$

The mean connection speed is 1 MBPS and the standard deviation is 0.1443 MBPS.

b) What is the probability that the connection speed will be less than 0.8 MBPS at any given time?

$P(X \leq 0.8) = \frac{0.8 - 0.75}{1.25 - 0.75} = 0.1$

10% probability that the connection speed will be less than 0.8 MBPS at any given time

c) What is the probability that the connection speed will be between 0.875 MBPS and 1.125 MBPS at any given time?

$P(0.875 \leq x \leq 1.125) = \frac{1.125 - 0.875}{1.25 - 0.75} = 0.5$

50% probability that the connection speed will be between 0.875 MBPS and 1.125 MBPS at any given time

Answer from: Quest

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

= $\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)$

side j'k'=distance between j' and k'

= $\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)$

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

Answer from: Quest

i would say c

step-by-step explanation:

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