A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football players, 52% are basketball players, and 9% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that he is either a football player or a basketball player?

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player =

The probability that athlete is a basketball player =

The probability that athlete is both basket ball player and  football player =

We have to find the probability that an athlete chosen is either a football player or a basketball player .

Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

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step-by-step explanation: