A road perpendicular to a highway leads to a farmhouse located 9 mile away. An automobile traveling on the highway passes through this intersection at a speed of 45mph. How fast is the distance between the automobile and the farmhouse increasing when the automobile is 7 miles past the intersection of the highway and the road?

27.63 mph

Step-by-step explanation:

First we find the distance, p between the Car and the house using Pythagoras theorem.

Taking derivatives of:

Since the farmhouse does not move, its speed

Therefore:

The distance between the automobile and the farmhouse is increasing at a rate of 27.63mph.

what shape is

step-by-step explanation:

well if you round, things become much more simple. round 5.95 to 6, 4.25 to 4, and 1.05 to 1. now, add 6+4+1 and that would equal 11. so the items together would equal to about $11.