The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the continuous rate of growth of this bacterium population? Your answer is __ percent B) what is the initial population of the culture (at t=0) your answer is __ C) how many bacteria will the culture contain at time t=5 ? Your answer is __ Round to the nearest bacteria

Using the exponential function, it is found that:

a) 45 percent.

b) 950.

c) 9013 bacteria.

A exponential function is modeled by:

In which:

In this problem, the model is:

Hence, , and:

a) 45 percent.

b) 950.

Item c:

At t = 5, we have that:

So 9013 bacteria.

A similar problem is given at link

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950

a) rate of growth is

Bacteria growth model N(t) = no

Where r is the growth rate

hence r = 0.45

              = 45%

b) Initial population of culture at t = 0

n(0) = 950

       = 950

       = 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) =  950

      = 950

      = 9013.35

      = 9013 bacteria

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form