What is the solution to this system of linear equations 3x-2y=14 5x+y=32

Multiply 2 in the 5x+y=32 so that we can eliminate the "y"

From 5x(2)+(2)y=32(2),

Then start eliminating the y,

[3x+10x = 13x] [-2y+2y = 0] [14+64 = 78]

Therefore, but we are not done yet, we need to find the value of y.

Substitute x = 6 in any equations but only one equation so I'll substitute in 5x+y=32 instead.

Therefore, y = 2.

So the answer is x = 6, y = 2 or (6,2)

it is true

step-by-step explanation:

all the combinations add up i used   calculator

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~