In ΔKLM, the measure of ∠M=90°, LK = 89, ML = 80, and KM = 39. What ratio represents the tangent of ∠K?

only 10/60 isn't equivalent

hope this : )

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it