A 3-foot-tall mailbox casts a shadow that is 1.8 feet long. At the same time, a nearby street lamp casts a shadow that is 12 feet long. How tall is the street lamp?

20 feet tall

Step-by-step explanation:

If these are at the same angle, which i'm assuming they are, the following would happen:

Put length of 1 item over its shadows length equal to 2nd items length over its shadow. Put x in the place you want to find (Lamp in this case)

(3/1.8)=(x/12)

Cross multiply

36=1.8x

Divide by 1.8 on both sides

20=x

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

10 you would take 50/ .2

step-by-step explanation: