The quadratic function f(x) has a turning point at (-3,8). if the function g is defined by g(x)=-f(x+5) for all values of x then at which of the following points will g(x) have a turning point?
(1) (-8,-8)
(2) (5,-3)
(3) (8,-8)
(4) (-2,8)

(-8,-8)

Step-by-step explanation:

We have that f(x) has a guy point at (-3,8).

If the function g is defined as:

then we want to find the turning point of g(x).

Note that from the above transformation, g is obtained by shifting f to the left, 5 units.

This will move the vertex to (-8,8).

This is then followed by a reflection in the x-axis.

The new vertex will be at;(-8,-8)

three-fourths of an hour

36÷48=0.75

0.75=

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3