What is the value of the discriminant?
2K2 = 10k - 2

84

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 : a ≠ 0

Then the discriminant is Δ = b² - 4ac

2k² = 10k - 2 ( subtract 10k - 2 from both sides )

2k² - 10k + 2 = 0 ← in standard form

with a = 2, b = - 10 and c = 2, thus

b² - 4ac = (- 10)² - (4 × 2 × 2) = 100 - 16 = 84

2 5/8 is the final answer! : )

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752