A study of college football games shows that the number of holding penalties assessed has a mean of 2.2 penalties per game and a standard deviation of 0.9 penalties per game. What is the probability that, for a sample of 40 college games to be played next week, the mean number of holding penalties will be 2.45 penalties per game or more? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places

Computation is approximately 1.2345

Step-by-step explanation:

Given:

Mean= 2.2 per game

Standard deviation= 0.9

Total college games =40

Penalties per game= 2.45

So,

Standard error has to be calculated which is defined as:

standard deviation is called the standard error. It's a measure of the average difference between each sample mean and the population mean.

There in lies its significance; it is a measure of how much error there is on our sampling procedures.

Standard error=

       ⇒p(x>2.45)= p(z>2.45-2.2)(1.1√40)

       ⇒1.2345

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7  

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!