Please help me with this

a=4, b=-8, c=-3

Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.

The standard form is ax^2+bx+c.

A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°