The energy usages per day (in kilowatt-hours) of houses on Hamlet Avenue are listed below. \qquad 30, 23, 38, 36, 3330,23,38,36,3330, comma, 23, comma, 38, comma, 36, comma, 33 Find the mean energy usage per day

32 kilowatt-hours.

Step-by-step explanation:

The energy usages per day (in kilowatt-hours) of houses on Hamlet Avenue are listed below:

30, 23, 38, 36, 33.

Therefore, the mean energy usage per day of the houses of Hamlet Avenue will be

=

= 32 kilowatt-hours.

The mean of n numbers is given by, . (Answer)

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: