Solve for q.
a=qb+r
What is q equal to?
q=a−r−b
q=a−r/b
q=a/b−r
q=a/rb

The given equation is

We need to solve the equation for q.

Value of q:

Let us determine the value of q from the equation

Subtracting both sides of the equation by r, we get;

Now, dividing both sides of the equation by b, we have;

Simplifying the terms, we get;

Therefore, the value of q is

Hence, Option B is the correct answer.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.