Seventy percent of rivets from vendor A meet a certain strength specification, and 80% of rivets from vendor B meet the same specification. If 510 rivets are purchased from each vendor, what is the probability that more than 775 of the rivets meet the specifications?

The probability that more than 775 of the rivets meet the specifications is 0.2327.

Step-by-step explanation:

Let X₁ and X₂ be the number of rivets that meet specification from vendor A and B respectively.

The proportions of rivets that meet specification from vendor A is, p₁.

The proportions of rivets that meet specification from vendor B is, p₂.

The sample of rivets selected from each vendor is, n₁ = n₂ = 510.

The random variables X₁ and X₂ follow Binomial distribution.

But, since the sample selected from each population is large a Normal approximation to Binomial can be used if:

Check the conditions for both the population as follows:

Thus, the Normal approximation to Binomial can be used.

Since both sample are independent then the distribution of X₁ + X₂ is:

Compute the probability of the event (X₁ + X₂ > 775) as follows:

*Use a standard normal table.

Thus, the probability that more than 775 of the rivets meet the specifications is 0.2327.

the option best identifies the textual evidence that supports this conclusion is c.) when an argument is over, how many weighty reasons does a man recollect which his heat and violence made him utterly forget? in order to recognize textual evidence is to identify the topic sentence where the author states the main idea. textual evidence is what supports the topic sentence or main idea of a passage.