Helen is helping plan a trip for three classes at her son's school. School rules say that classes on trips must have 1 adult for every 6 children. One class has 24 children; one has 26 children; and the third has 28 children. Each class has 1 teacher. How many OTHER adults are needed for the trip?

The first class needs four (4) adults, the second class needs five (5) adults, and the third class needs five (5) adults.

Since, each class has one adult,

Therefore, the number of other adults needed for the trip is Eleven (11) adults

Step-by-step explanation:

School rules say that classes on trips must have 1 adult for every 6 children

First class has 24 children

1 : 6

x : 24

Cross multiplication

6x = 24

∴ x = 4

So, the first class needs four (4) adults.

Second class has 26 children

1 : 6

x : 26

Cross multiplication

6x = 26

∴ x = 4.3

So, the second class needs five (5) adults where one adult will be with three (3) children.

Third class has 28 children

1 : 6

x : 28

Cross multiplication

6x = 28

∴ x = 4.7

So, the third class needs five (5) adults where one adult will be with three (4) children

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

about 168 miles

step-by-step explanation: