50 Points!!
Graph the function. Compare the graph to the graph of f(x) = x²
Let f(x) = 3x²− 1 and g(x) = f(x) + 3.
a. Describe the transformation from the graph of f to the graph of g.
Then graph f and g in the same coordinate plane.
b. Write an equation that represents g in terms of x.
Before graphing! Explain!
What do you notice?
Vertical Translation:
Vertex:

a) g(x) = f(x) + 3

So g(x) is a vertical translation of f(x), 3 units upwards

b) g(x) = 3x² - 1 + 3

g(x) = 3x² + 2

The graph has shifted 3 units upwards, so has the vertex.

The vertex of f is (0,-1)

Whereas the vertex of g is (0,2)

-1 + 3 = 2

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.