There is a cone-shaped pile of salt on the floor 3 inches tall and with a diameter of 10 inches. what is the scant of the anger that cone makes with the ground

The scant of the cone is 5.83 in

Explanation:

Given:

Height, h of the cone = 3 in

Diameter, d = 10 in

Radius, r = 10/2 = 5 in

Scant, L = ?

Height, diameter and cone will form a right angle triangle.

Using pythagoras theorm:

(L)² = (h)² + (d)²

(L)² = (3)² + (5)²

(L)² = 34

L = 5.83 in

Therefore, the scant of the cone is 5.83 in

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2