You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. You would like to have 8.5 lbs of a candy mixture that sells for $2.70/lb. How much of each candy will you need to obtain the desired mixture?

You will need

lbs of the cheaper candy
and
lbs of the expensive candy.

You will need 3.5lbs of the cheaper candy

and 5 lbs of the expensive candy.

Step-by-step explanation:

Let x represent the number of pounds of the cheaper candy that you would need.

Let y represent the number of pounds of the expensive candy that you would need.

You would like to have 8.5 lbs of a candy mixture. It means that

x + y = 8.5

You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. The candy mixture would sell for $2.70/lb. It means that the total cost of the mixture would be 8.5 × 2.7 = $22.95. The expression would be

1.7x + 3.4y = 22.95- - - - - - - - - - - 1

Substituting x = 8.5 - y into equation 1, it becomes

1.7(8.5 - y) + 3.4y = 22.95

14.45 - 1.7y + 3.4y = 22.95

- 1.7y + 3.4y = 22.95 - 14.45

1.7y = 8.5

y = 8.5/1.7

y = 5

x = 8.5 - y = 8.5 - 5

x = 3.5

40 x 50 = 2000

step-by-step explanation: