A store sells tents, sleeping bags, and camp stools. A customer buys a tent, 3 sleeping bags, and 4 camp stools for $170. The price of the tent is 9 times the cost of a camp stool. The cost of a sleeping bag is $30 more than the cost of a camp stool. Find the cost of each item.

the cost of a tent is $45

the cost of a sleeping bag is $35

the cost of a camp stool is $5

Step-by-step explanation:

Let x represent the cost of a tent.

Let y represent the cost of a sleeping bag.

Let z represent the cost of a camp stool.

A customer buys a tent, 3 sleeping bags, and 4 camp stools for $170. It means that

x + 3y + 4z = 170- - - - - - - - - - - - - - -1

The price of the tent is 9 times the cost of a camp stool. It means that

x = 9z

The cost of a sleeping bag is $30 more than the cost of a camp stool. It means that

y = z + 30

Substituting x = 9z and y = z + 30 into equation 1, it becomes

9z + 3(z + 30) + 4z = 170

9z + 3z + 90 + 4z = 170

9z + 3z + 4z = 170 - 90

16z = 80

z = 80/16

z = 5

y = z + 30 = 5 + 30

y = 35

x = 9z = 9 × 5

x = 45

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

-5, your answer was correct