A plant biologist studies the height of sunflowers. He measures a large sample of sunflowers and creates a probability distribution. The distribution is normal in shape with mean 112 cm and standard deviation 16 cm. What is the probability (approximately) that a sunflower will be less than 136 cm tall?

Probability that a sunflower will be less than 136 cm tall is 0.9332.

Step-by-step explanation:

We are given that a plant biologist studies the height of sunflowers. He measures a large sample of sunflowers and creates a probability distribution.

The distribution is normal in shape with mean 112 cm and standard deviation 16 cm.

Let X = height of sunflowers

So, X ~ N()

The z-score probability distribution for single selected value is given by;

                Z =  ~ N(0,1)

where, = population mean height = 112 cm

             = standard deviation = 16 cm

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that a sunflower will be less than 136 cm tall is given by = P(X < 136 cm)

    P(X < 136 cm) = P( < ) = P(Z < 1.50) = 0.9332

The above probabilities is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.

Hence, probability that a sunflower will be less than 136 cm tall is 0.9332.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

no he doesnt because "-16' is negatiive

step-by-step explanation: