Solving systems using substitution

2) y = x + 8
y = -4x - 12

4) y = 3x - 4
y = x - 4

2) x=-4 y=4 4) x=0 y=-4

Step-by-step explanation:

2) Step: Substitute x+8 for y in y=−4x−12:

y=−4x−12

x+8=−4x−12

x+8+4x=−4x−12+4x  (Add 4x to both sides)

5x+8=−12

5x+8+−8=−12+−8 (Add -8 to both sides)

5x=−20

5x /5 = −20 /5 (Divide both sides by 5)

x=−4

Step: Substitute −4 for x in y=x+8:

y=x+8

y=−4+8

y=4 (Simplify both sides of the equation)

x=−4 and y=4

4) Step: Substitute 3x−4 for y in y=x−4:

y=x−4

3x−4=x−4

3x−4+−x=x−4+−x  (Add -x to both sides)

2x−4=−4

2x−4+4=−4+4  (Add 4 to both sides)

2x=0

2x/2  =  0 /2 (Divide both sides by 2)

x=0

Step: Substitute 0 for x in y=3x−4:

y=3x−4

y=(3)(0)−4

y=−4 (Simplify both sides of the equation)

x=0 and y=−4

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