Mathematics, 27.03.2020 02:30 garciavergaraana
Jarvis needs to determine the distance across a lake. However, he can't measure this distance directly over the water. So, he set up a situation where he could use the measurements of two similar triangles to find the distance across the lake.
He selects a point X such that XZ is perpendicular to VZ, where V is a point at the other end of the lake. He then picks a point Y on XZ. From point Y, he finds point W on XV such that WY is parallel to VZ.
If XY = 1,952 feet, WY = 976 feet, and XZ = 5,856 feet, what is the length of VZ, the distance across the lake?
A.
2,928 feet
B.
3,904 feet
C.
244 feet
D.
325 feet
Answers: 2
Mathematics, 21.06.2019 16:30, enchantednights
Look at attachment. has all info needed. need
Answers: 1
Mathematics, 21.06.2019 20:30, noah12345678
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Mathematics, 21.06.2019 22:00, angeloliv1012
Solve 2 - 3 cos x = 5 + 3 cos x for 0° ≤ x ≤ 180° a. 150° b. 30° c. 60° d. 120°
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