How do I factor 4p^8-60p^4-225p^2

this is how you would do it on paper

Step-by-step explanation:

For a polynomial of the form

a

x

2

+

b

x

+

c

, rewrite the middle term as a sum of two terms whose product is

a

⋅

c

=

4

⋅

−

1

=

−

4

and whose sum is

b

=

3

.

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Reorder terms.

4

p

2

−

q

2

+

3

p

q

Reorder

−

q

2

and

3

p

q

.

4

p

2

+

3

p

q

−

q

2

Factor

3

out of

3

p

q

.

4

p

2

+

3

(

p

q

)

−

q

2

Rewrite

3

as

−

1

plus

4

4

p

2

+

(

−

1

+

4

)

(

p

q

)

−

q

2

Apply the distributive property.

4

p

2

−

1

(

p

q

)

+

4

(

p

q

)

−

q

2

Remove unnecessary parentheses.

4

p

2

−

1

p

q

+

4

(

p

q

)

−

q

2

Remove unnecessary parentheses.

4

p

2

−

1

p

q

+

4

p

q

−

q

2

Factor out the greatest common factor from each group.

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p

(

4

p

−

1

q

)

+

q

(

4

p

−

q

)

Factor the polynomial by factoring out the greatest common factor,

4

p

−

1

q

.

(

4

p

−

1

q

)

(

p

+

q

)

Rewrite

−

1

q

as

−

q

.

(

4

p

−

q

)

(

p

+

q

)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180