The given region is the combination of a semicircle with radius 2 cm and a right isosceles triangle with base length 4 cm. Find the area of the given region using the formula for the area of a circle, A = πr2 where r is the circle's radius, and the formula for the area of a triangle, A = bh/2 where b and h are the lengths of the triangle's base and height, respectively. Remember, a semicircle's area is one half the area of the circle with the same radius.

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation:

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol