5/6 + 1/3 adding fractions with unlike denominators.

7/6 or 1 1/6

Step-by-step explanation:

First, convert all the fractions so that they have like denominators, using LCM, or Least Common Multiple. This means that you must find the least common multiple that the two denominators share, which in this case is 6. 6 will become the denominator for both fractions  At this point, to find the numerators, I use my own sort of mental method to get the answer. I first take the LCM and divide it by the denominator of one of the fractions (let's do 1/3) which would give me 2. Then multiply this number by the numerator of the same fraction you started with, which is 2 again. So, your new fraction is 2/6. Since 5/6 already has a denominator of 6, you don't have to do anything, but if it did, you would just repeat the same method. At this point, the new problem is 5/6 + 2/6. Add like normal, and leave in either improper form (7/6) or mixed numbers (1 1/6) based on instructions.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !