A family spends $35.00 on 5 drinks and 5 bags of popcorn at the movie theater. Each drink costs $1.75 and each bag of popcorn costs x dollars. The equation models this relationship.5(x+1.75)=35 How much does 1 bag of popcorn cost?

$5.25

Step-by-step explanation:

The question says that a family probably attended an event(they probably went to watch a movie show) and ordered for 5 bags of popcorn and 5 drinks at the theater.

And it also says that each drink costs $1.75 dollars and a bag of popcorn costs?.

But we were given the equation which models the relationship as 5(x+1.75)=35.

With this equation we will be able to find out how much each bag of popcorn costs and if possible,we can also calculate how much 10 bags of popcorn and 9 drinks costs and vice versa all just for fun.

Back to business,

5(x+1.75)= 35

Open up the bracket and we will have:

5x+8.75= 35

Subtract 8.75 from both side:

5x+8.75 - 8.75= 35 - 8.75

5x= 26.25

Now divide both sides by 5 so as to get x

5x/5= 26.25/5

X= $5.25

Therefore,the price of each bag of popcorn is $5.25

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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