A grain silo is composed of a cylinder and a hemisphere.

The diameter is 4.4 meters. The height of its cylindrical

portion is 6.2 meters.

Vhat is the approximate total volume of the silo? Use 3.14

for r and round the answer to the nearest tenth of a cubic

meter

6.2 m

37 1 m

71.9 m3

116.5 m

130.8 m

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 The approximate total volume of the silo is  116.5 m3

Step-by-step explanation:

Hi, the volume of the silo is equal to: volume of the cylinder + volume of the hemisphere:

Volume of the cylinder:

V = π x r²x h

Where:

R = radius (in this case, to obtain the radius we have to divide the diameter by two since radius = diameter /2)

h = height

Replacing with the values given:

V = π x r²x h = 3.14 x (4.4/2) ²6.2= 3.14 x (2.2)²x 6.2 = 94.22512 m3

And for the hemisphere:

Volume of the hemisphere: 2/3 x π x r3

Replacing with the values given;

v= 2/3 x 3.14 x 2.2∧3= 22.28m3

Finally, adding both results:

Volume of the silo = volume of the cylinder + volume of the hemisphere:

94.22 m3+ 22.28m3 = 116.5 m3

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2