X^2+3x+c=7/4+c
What is the value of c?

x= -3½ or ½

Step-by-step explanation:

x²+3x+c=7/4+c

Rearranged

x²+3x=7/4+c-c

(x²+3x)=7/4

Multiply both sides by 4

4(x²+3x)=4(7/4)

4x²+12x=7

Rearranged

4x²+12x-7=0

Factorise

4x²+14x-2x-7=0

2x(2x+7)-1(2x+7)=0

(2x+7)(2x-1)=0

2x+7=0 or 2x-1=0

2x=0-7 or 2x=0+1

2x= -7 or 2x=1

Divide both sides by 2

2x/2= -7/2 or 2x/2=1/2

x= -3½ or x=½

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: