A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the
spring push when you compress it from 40 cm long down to 15 cm long?

Hooke's Law Formula:

F = k * x

•F = Force

•K = Spring Constant

•X = spring variation

F = ?

K = 70 N/m

X = 40cm - 15cm (ending length - starting length).

But we need to change 'cm' to 'm', so we will divide the result of X by 100.

X= 25/100 → 0.25m

F = 0.25 * 70

F = 17.5 N

- mbsilvaf

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later