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CLEAR CHECK

Part A: The solution to 3x−13=−4 is x=3.

The solution to 3x−13>−4 is x { } 3.

A value for x that is a solution to 3x−13=−4 is x= { }

. A value for x that is a solution to 3x−13>−4 is x= { }

.

Part B: The solution to −3x−13=−4 is x=−3.

The solution to −3x−13>−4 is x { } −3.

A value for x that is a solution to −3x−13=−4 is x= { }

. A value for x that is a solution to −3x−13>−4 is x={ }

The correct answer is

3x − 13 > −4 is x { > } 3.

3x − 13 = −4 is x= { 3 }.

3x − 13 > −4 is x= { 5 } .

−3x − 13 > −4 is x { < } −3.

−3x −13 = −4 is x= { -3 } .

−3x − 13 > −4 is x= { -5 }.

Step-by-step explanation:

Part A: The solution to 3x − 13 = −4 is x=3.

The solution to 3x − 13 > −4 is x { > } 3.

⇒ 3x > 13 - 4

⇒ 3x > 9

⇒ x > 3.

A value for x that is a solution to 3x − 13 = −4 is x= { 3 }

A value for x that is a solution to 3x − 13 > −4 is x= { 5 } .

Any number more than 3 can be considered as a solution to this inequality.

Part B: The solution to −3x −13 = −4 is x=−3.  

The solution to −3x − 13 > −4 is x { < } −3.

⇒ -3x > 13 - 4

⇒ -3x > 9

⇒ x < -3.

A value for x that is a solution to −3x −13 = −4 is x= { -3 }

A value for x that is a solution to −3x − 13 > −4 is x= { -5 }

Any number less than -3 can be considered as a solution to this inequality.

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages