What is the area of an isosceles right triangle whose hypotenuse is (7 √2)?

Write your answer as a decimal to the nearest tenth.

Area of an isosceles right triangle is 24.5

Step-by-step explanation:

Given that triangle is an isosceles right angle which means that two side of the triangle are equal and one of the angle is .

Consider triangle (Refer to attachment),

.

Since both sides are equal angle opposite to both sides are same.

Now applying pythagoras theorem to ,

Assume ,

Substituting the value,

Simplifying,

Dividing by 2,

Taking square root on both sides,

Formula for area of triangle is given as,

Now AB=height,BC=base.

Substituting the value,

So, area of an isosceles right triangle is 24.5

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680