In pigeons, the allele for normal feathers (F) is dominant to the allele for frizzy feathers (f). If a purebred, normal-feathered bird is crossed with a frizzy feathered bird, what percentage of the offspring will possess normal feathers?

Step-by-step explanation:

100% because if you do a punnett square there is always a dominant alle so they are all Ff, when there is a dominant alle present the offspring gets the dominant trait.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

x = 23.78

step-by-step explanation: