Wyatt’s eye-level height is 120 ft above sea level, and shawn’s eye-level height is 270 ft above sea level. how much farther can shawn see to the horizon? use the formula d = square root of 3h/2, h> 0 with d being the distance they can see in miles and h being their eye-level height in feet.

The answer is 6.7 miles further.

It is given:

Wyatt’s eye-level height - h₁ = 120ft
Shawn’s eye-level height - h₂ = 270ft

The distance that Wyatt can see:


The distance that Shawn can see: 


The question is how much farther can Shawn see to the horizon, so we need to subtract the results:
20.12 - 13.42 = 6.7 miles

hope it is correct if not i'm srry i tried to