The length of side AC¯¯¯¯¯¯ in ΔABC is 5 units.

Triangle A B C on a coordinate plane with coordinates A 1 comma 1, B 4 comma 1, and C 4 comma 5.

What is the perimeter of ΔABC?
12 units
13 units
15 units
16 units

The perimeter of ΔABC = 12 units

Step-by-step explanation:

From the given triangle ABC on a coordinate plane, we can observe that:

The length of AB is the distance between A(1, 1) and B(4, 1)

so using the distance formula

similarly the length of BC is the distance between B(4, 1) and C(4, 5)  

Therefore, the perimeter of the triangle ABC can be obtained using the formula:

P = AB + BC + AC

  =  3 + 4 + 5

  = 12 units

Therefore, the perimeter of ΔABC = 12 units

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

215.92 dollars is the answer