Question 1 (1 point)
Saved
What is the solution to the following equation?

4x + 15 = 31

Question 1 options:

x = 11.5

x = 4

x = 12

x = -7.25

Question 2 (1 point)
Saved
What is the solution set for the inequality?

-3x + 10 > -5

Question 2 options:

x > -5

x < -5

x < 5

x > 5

Question 3 (1 point)
What is the solution to the model below?

Question 3 options:

x = 7

x = 2

x = 3

x = 1

Question 4 (1 point)
Solve the inequality.

-2x - 1 ≥ 9

Question 4 options:

x ≤ 5

x ≥ -5

x ≤ -5

x ≥ 5

Question 5 (1 point)
Solve for x.

-0.5x + 3.55 = -4.5

Question 5 options:

x = -12.55

x = -16.1

x = 12.55

x = 16.1

What is the perimeter of trapezoid jklm? + units 2 + + units 9 + units 9 + + units

Expresa commuter train leaves downtown sation and travels at a average speed of 55 miles per hour towards the north side sation, which is 50miles away. thirty minutes later, express commuter train #7 leaves north side and travels at a average speed of 35miles per hour towards downtown sation. at the moment the two trains pass each other, how far(in miles) is train #12 from the downtown sation and how long(in minutes) has the #12 train been traveling

Since opening night, attendance at play a has increased steadily, while attendance at play b first rose and then fell. equations modeling the daily attendance y at each play are shown below, where x is the number of days since opening night. on what day(s) was the attendance the same at both plays? what was the attendance? play a: y = 8x + 191 play b: y = -x^2 + 26x + 126 a. the attendance was never the same at both plays. b. the attendance was the same on day 5. the attendance was 231 at both plays on that day. c. the attendance was the same on day 13. the attendance was 295 at both plays on that day. d. the attendance was the same on days 5 and 13. the attendance at both plays on those days was 231 and 295 respectively.