A division of a company has over 200 employees, 40% of which are male. Each month, the company randomly
selects 8 of these employees to have lunch with the CEO.
What are the mean and standard deviation of the number of males selected each month?

You may round your answers to the nearest tenth.
mean:?
males

standard deviation:?
males

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step-by-step explanation:

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answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

probably .5

i can on others if necessary.