A town council wants to estimate the proportion of residents who are in favor of a proposal to upgrade the computers in the town library. A random sample of 100 residents was selected, and 97 of those selected indicated that they were in favor of the proposal. Is it appropriate to assume that the sampling distribution of the sample proportion is approximately normal?

Since n(1-p) < 5, it is not appropriate to assume that the sampling distribution of the sample proportion is approximately normal.

Step-by-step explanation:

Binomial probability distribution:

Probability of x sucesses on n repeated trials, with p probability.

Can be approximated to the normal distribution if:

np > 5 and n(1-p) > 5

In this problem:

A random sample of 100 residents was selected, and 97 of those selected indicated that they were in favor of the proposal.

This means that

Is it appropriate to assume that the sampling distribution of the sample proportion is approximately normal?

np = 100*0.97 = 97 > 5

n(1-p) = 100*0.03 = 3 < 5

Since n(1-p) < 5, it is not appropriate to assume that the sampling distribution of the sample proportion is approximately normal.

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads