4(tan(x) − cot(x)) tan2(x) − cot2(x) = 2 sin(2x) Factor the denominator and then simplify. 4(tan(x) − cot(x)) tan2(x) − cot2(x) = 4(tan(x) − cot(x)) (tan(x) + cot(x)) = tan(x) + cot(x) Use the Reciprocal Identities and simplify the compound fraction. = sin(x) cos(x) + cos(x) sin(x) = sin2(x) + cos2(x) Use a Pythagorean Identity and a Double-Angle Formula to simplify. = 1 =

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(01.02 lc) angle abc has point e on ray ba and point d on ray bc. points e and d are equidistant from point b. to bisect angle abc, which of the following needs to be identified for the construction? the distance between points e and d the point in the angle that is equidistant from points e and d the endpoint of rays ba and bc the point outside of the angle that is equidistant from points e and d

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.