The coordinates of the vertices of A PQR are P(-3, 4). Q(-3, 1), and R(-1, 1). The
coordinates of the vertices of A P'Q Rare P'(-6, – 5). Q(-6, -1), and R'(-4, -1)
Which statement correctly describes the relationship between A PQR and A PQR' ?
A PQR is congruent to APQR because you can map A PQR to APQR
using a reflection across the x-axis followed by a translation 3 units to the left, which
is a sequence of rigid motions.
A PQR is congruent to A P Q R' because you can map A PQR to APQR'
using a translation 3 units to the left followed by a reflection across the x-axis, which
is a sequence of rigid motions.
A PQR is congruent to A P'Q R' because you can map A PQR to APQR
using a reflection across the x-axis followed by a translation 1 unit down, which is a
sequence of rigid motions.
A PQR is not congruent to A P'Q R' because there is no sequence of rigid
motions that maps A PQR to A P'Q R

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240