Hile sitting in physics class one day, you begin to ponder the workings of the analog clock on the classroom wall. You notice as the hands sweep in a continuous motion that there are exactly t = 37 minutes left in class. Randomized Variables t = 37 minutes show answer No Attempt 14% Part (a) Through what angle (in radians) will the second hand turn before the end of class?

Second hand will turn through 74π radians.

Step-by-step explanation:

There are 37 minutes left in the class. We need to find by how much angle will the second hand turn before the end of the class.

When a second hand completes one full rotation along the clock it covers 360 degrees and completes 60 seconds.

This means:

In 60 seconds, the second hand turns by 360 degrees

Since, 60 seconds = 1 minute, we can write:

In 1 minute, the second hand turns = 360 degrees

360 degrees is equal to 2π radians. So,

In 1 minute, the second hand turns = 2π radians

Multiplying both sides by 37 gives us:

In 37 minutes, the second turns = 2π radians x 37 = 74π radians

the bottom of the spinner is not flat.

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3