30) Shayna and Nicole are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Shayna sold 7 apple pies and 2 blackberry pies for a total of $148. Nicole sold 7 apple pies and 4 blackberry pies for a total of $184. What is the cost each of one apple pie and one blackberry pie?

A) apple pie: $18, blackberry pie: $16

B) apple pie: $18, blackberry pie: $14

C) apple pie: $25, blackberry pie: $27

D) apple pie: $16, blackberry pie: $18

Shayna and Nicole are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Shayna sold 7 apple pies and 2 blackberry pies for a total of $148. Nicole sold 7 apple pies and 4 blackberry pies for a total of $184-   so the cost of the (D) apple pie: $16, blackberry pie: $18

Step-by-step explanation:

Let A = the price of an apple pie and let B = the price of a blackberry pies. Using the information  in the question  we get  two equations:

7A + 2B = $148>(i)

7A + 4B = $184>(ii)

Making  use of the Elimination Method . We  multiply the bottom equation by -1 and then add the two equations together, we get:

7A + 2B = 148

-7A - 4B = -184

-2B = -36

B = 36/2=18

The cost of a blackberry pies is $18.

To find the cost of an apple pie, we simply substitute B = 18 in one of the equation.So choosing equation (i) we get

7A + 2(18) = 148

7A + 36 = 148

7A = 112

A = 16

The cost of an apple pie is $16

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.