Find the slope and y-intercet of the line that is perpendicular to y= 3 x − 3 and passes through the point ( − 8,-2)

Step-by-step explanation:

If a line has a slope of , then the line perpendicular to it has a slope of (opposite reciprocal).

With this, we can construct a line in slope-intercept form:

Where is the slope of the line and is the y-intercept.

We already know the slope of the line, so we can plug it into the equation:

We also know that the line passes through the point , so we can plug this into the equation to get :

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: