The mayor gets elected every four years. Treasurer gets elected every six years. Both were elected this year. How many years before the election happens in the same year.

Step-by-step explanation:

The mayor gets selected once in every 4 years.

So, the number of years the mayor elections takes place

=  1, 4 ,8, 12, 16, 20, 24, 28,

Now, the Treasurer gets selected once in every 6 years.

So, the number of years the Treasurer elections takes place

= 1,  6, 12, 18, 24, 30

Now,as we can see from both statements, the year in which both elections happen are the common factors of 4 and 6.

The first common factor of 4 and 6 is 12.

So,in twelfth year both elections happen in the same year again.

Hence, there are 11 years before the elections happen in the same year.

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step-by-step explanation:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x