Mathematics, 23.03.2020 22:43 allytrujillo20oy0dib

Wo balls are chosen randomly from an um containing 8 white, 4 black, and 2 orange balls. Suppose that we win $2 for each black ball selected and we lose $1for each white ball selected. LetXdenote our winnings. What are the possible valuesofX, and what are the probabilities associated with each value

Answers: 1

Show answers

Answers

Answer from: twalters88

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (W), 4 black (B) and 2 orange (O) balls.

The winning and losing criteria are:

Win $2 for each black ball selected.Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, ${14\choose 2}=91$ ways.

The distribution of amount won or lost is as follows:

Outcomes: WW WO WB BB BO OO

X: -2 -1 1 4 2 0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, ${8\choose 2}=28$ ways.

The probability of WW is,

$P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077$

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, ${8\choose 1}\times {2\choose 1}=16$ ways.

The probability of WO is,

$P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758$

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, ${8\choose 1}\times {4\choose 1}=32$ ways.

The probability of WB is,

$P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516$

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, ${4\choose 2}=6$ ways.

The probability of BB is,

$P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659$

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, ${4\choose 1}\times {2\choose 1}=8$ ways.

The probability of BO is,

$P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879$

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, ${2\choose 2}=1$ ways.

The probability of OO is,

$P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110$

The probability distribution of X is:

Outcomes: WW WO WB BB BO OO

X: -2 -1 1 4 2 0

P (X): 0.3077 0.1758 0.3516 0.0659 0.0879 0.0110

Answer from: Quest

The density of the cube is 40

Answer from: Quest

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

Other questions on the subject: Mathematics

Mathematics, 20.06.2019 18:02, ratpizza

Bradley completed latex: \frac{3}{5} 3 5 of his homework. what percent of his homework does he still need to complete?

Answers: 1

continue

Mathematics, 21.06.2019 17:30, jruiz33106

1mile equals approximately 1.6 kilometers. which best approximates the number of miles in 6 kilometers?

Answers: 1

continue

Mathematics, 22.06.2019 00:00, madisonwr

Afarmer has decided to divide his land area in half in order to plant soy and corn. calculate the area of the entire area so he knows how much soil is needed. each bag of soil covers 20 square yards. how many bags should the farmer purchase? (4 points) 1 bag 2 bags 3 bags 4 bags

Answers: 2

continue

Mathematics, 22.06.2019 01:20, lauretta

Aprobability experiment is conducted in which the sample space of the experiment is s={7,8,9,10,11,12,13,14,15,16,17,18 }, event f={7,8,9,10,11,12}, and event g={11,12,13,14}. assume that each outcome is equally likely. list the outcomes in f or g. find p(f or g) by counting the number of outcomes in f or g. determine p(f or g) using the general addition rule.

Answers: 2

continue

You know the right answer?

Wo balls are chosen randomly from an um containing 8 white, 4 black, and 2 orange balls. Suppose tha...