A builder has some red and grey bricks. The red bricks weigh 3 kilograms each, and the grey bricks weigh 2 kilograms each. If the total weight of all 7 bricks is 17 kilograms, how many of each type of brick does Omar have?

?=red bricks

?=grey bricks

you have to guess and check word problems
I have to finish the sums by today

 3 red bricks and 4 grey bricks

Step-by-step explanation:

You have 17 kg total with weights of 3 kg and 2 kg.

Since 17 is an odd number, subtract one 3 kg weight to get an even #.

17 - 1(3 kg) = 14      

14 ÷ 2 kg = 7

One 3 kg weight results in seven 2 kg weights = 8 total weights.

Since the given problem states that there are only seven weights, my guess was not correct.

Try Again:

Since we need and odd number of 3 kg weights, try three 3 kg weights

17 - 3(3 kg) = 8

8 ÷ 2 kg = 4

Three 3 kg weights and four 2 kg weights = 7 total weights.

Note that this can be solved mathematically using a system of equations:

Weight: 3r + 2g = 17

Quantity: r  +  g =  7

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²